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Atoms ‘X’ occupy corners and face centres of a cubic unit cell. Atoms ‘Y’ occupy edge centres and body centre. If one atom from corners,four atoms from edge centres and one atom from body centre are missing the formula of the compound would be
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Correct option is C
‘X’ occupies 7 corners (1 atom of ‘X’ are missing from corners) and 6 face centres.∴effective number of atoms of ‘X’ = 7×18+6×12=318‘Y’ occupies 8 edge centres (4 atoms of ‘Y’ are missing from edge centres)∴effective number of atoms of ‘Y’ = 8×14=84Ratio of atoms of ‘X’ to ‘Y’ =318:84=31 : 16Formula of the compound = X31Y16Talk to our academic expert!
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In a unit cell, atoms (A) are present at all corner lattices, (B) are present at alternate faces and all edge centers. Atoms (C) are present at face centers left from (B) and one at each body diagonal at distance of 1/4th of body diagonal from corner.
A tetrad axis is passed from the given unit cell and all the atoms touching the axis are removed. The possible formula of the compound left is
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