ATP+H2O→ADP+PO43−; ΔrG∘=−31kJ/mol Glucose + Fructose → Sucrose; ΔrG∘=23kJ/molA 100 ml solution is 0.5 (M) with respect to glucose and 0.8 (M) with respect to fructose. To this how many liters of gastric juice containing l0-2 (M) ATP is to be added to obtain maximum molarity of sucrose?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3 L
b
2.71 L
c
37.1 L
d
3.71 L
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Glucose + Fructose → Sucrose5×10−2mol 8×10−2molGlucose is the L.R. and maximum amount of sucrose to be obtained = 5 × 10-2 mol ∴ Energy required =23×5×10−2kJLet V ml of ATP solution is requiredV×10−5×31=23×5×10−2∴ V=23×531×103=3.71×103mL=3.71L
ATP+H2O→ADP+PO43−; ΔrG∘=−31kJ/mol Glucose + Fructose → Sucrose; ΔrG∘=23kJ/molA 100 ml solution is 0.5 (M) with respect to glucose and 0.8 (M) with respect to fructose. To this how many liters of gastric juice containing l0-2 (M) ATP is to be added to obtain maximum molarity of sucrose?