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ATP+H2O→ADP+PO43-;ΔrG0=-31kJ/molGlucose+Fructose→Sucrose; ΔrG0=23 kJ/molA 100ml solution is 0.5(M) with respect to glucose and 0.8(M) with respect to fructose. To this how many liters of gastric juice containing 31×10-5 M ATP is to be added to obtain maximum molarity of sucrose?

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a

3 L

b

2.71 L

c

37.1 L

d

3.71 L

answer is D.

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Detailed Solution

Glucose+Frucose → Sucrose 5×10-2 mol;8×10-2 mol Glucose is the L.R. and maximum amount of sucrose to be obtained =5×10-2 mol ∴ Energy required =23×5×10-2 kJ Let V vol of ATP solution is required V×10-5×31=23×5×10-2 ∴V=23×531×103=3.71×103 ml=3.71 L

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