Attainment of the equilibrium A(g)⇌2C(g)+B(g) gave the following graph. Find the correct option.(% dissociation = fraction dissociated x 100)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

At t=5sec equilibrium has been reached and Kc=40( mol/ litre )2

At t = 5 sec equilibrium has been reached and% dissociation of A is 2O%

At t = 5 sec equilibrium has been reached and o/o dissociation of A is 30%

None of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

A(s)⇌2C(s)+B(g) at t=0, [A]=10M from graph, [A]eq.=10(1-α)=8 , [C]=10(2α)=4, [B]=10 α=2 kc=[C]2[B]1[A]1=4×4×28 =4( mol/L)2Hence option(2) is correct.

Watch 3-min video & get full concept clarity