Q.

The average atomic mass of a mixture containing 79 mol% of  24Mg and remaining  21 mol% of  25Mg and  26Mg is 24.31. Then %mol of  26Mg is ___?

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a

5

b

20

c

10

d

15

answer is C.

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Detailed Solution

Let % mol of Mg  26 be x  '' . (21-x)25+x(26)+79×24100=24.31 x=10%
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