Q.

The average K.E. of one mole of an ideal gas in calories is equal to

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a

3 T

b

2 T

c

4 T

d

23T

answer is A.

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Detailed Solution

(KE)avg =32×n×R×T=32×2×T=3T
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Best Books for NEET
How to Join IIT after 10th
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The average K.E. of one mole of an ideal gas in calories is equal to