The average molar mass of chloride is 35.5 g mol−1. The ratio of 35Cl to 37Cl in naturally occuring chloride is close to:

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4:1

3:1

1:1

2:1

answer is B.

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Detailed Solution

Cl35 Cl37 mole fraction x 1−xMavg =x×35+(1−x)(37)=35.5⇒35x+37−37x=35.52x=32x=34C135C137=x(1−x)=3/41/4=3:1

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