Q.

The average molecular mass of a mixture of gas containing nitrogen and carbon dioxide is 36. The mixture contain 280 g of nitrogen, therefore, the amount of CO2 present in the mixture is

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a

440 g

b

44 g

c

220g

d

880 g

answer is A.

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Detailed Solution

Let amount of CO2 present = x g36=28028×28+x44×4428028+x4436=280+x10+x/44=(280+x)×44440+x or 15840+36x=12320+44x or 8x=3520x=35208=440g
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