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Q.

The average Xe - F bond energy is 34 kcal/mol, first I.E. of Xe is 279 kcal/mol, electron affinity of F is 85 kcal/mol and bond dissociation energy of F2 is 38 kcal/mol. Then, the enthalpy change for the reactionXeF4 →  Xe+ + F- + F2 + F will be

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a

367 kcal/mol

b

425 kcal/mol

c

292 kcal/mol

d

392 kcal/mol

answer is C.

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Detailed Solution

∆H=4EXe-F + ∆HIonisation  Xe → Xe+ -∆EF-F - ∆Heg  F → F- =4 × 34+279-85-38=136+279-123 =415-213=292 kcal/mol
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