A+B→A3B2 unbalancedA3B2+C→A3B2C2 unbalancedAbove two reactions are carried out by taking 3 moles each of A and B and one mole of C. Then which option is/are correct?
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a
1 mole of A3B2C2 is formed
b
Half mole of A3B2C2 is formed
c
3/2 mole of A3B2 is formed
d
Half mole of A3B2 is left finally
answer is B.
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Detailed Solution
Rewriting the given equations 3/2 A+B→1/2 A3B2 1/2 A3B2+C→1/2 A3B2C2C is a limiting reagent so A3B2C2 should contain only one mole of C therefore 1/2 mole of is considered and entire reaction is balanced accordingly.Therefore only 1/2 mole of A3B2C2 is formed.