A, B, C, D , E and F are the elements belonging to Second group of Modern periodic table. The correct trend of reducing power for these elements in aqueous solution is A $$=$$ F C D EB. The element ‘C’ in the sequence is

Question

A, B, C, D , E and F are the elements belonging to Second group of Modern periodic table. The correct trend of reducing power for these elements in aqueous solution is  A $$=$$ F > C > D > E>B. The element ‘C’ in the sequence is

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$$A)$$ Atomic radius…BeMg>Ca>Sr>Ra>Ba;$$C)$$ EN…..Be>Mg>$$Ca=Sr$$>Ba>Ra;$$D)$$ MP…Be>Ca>Sr>Ba>Ra>Mg ;$$E)$$ BP…Be>Ba>Ra>Ca>Sr>Mg ;$$F)$$ Density…..Ra>Ba>Sr>Be>Mg>Ca ;$$G)$$ Abundance in Earth's crust….Ca>Mg>Ba>Sr>Be>Ra ;$$H)$$ Hydration Enthalpy….$$Be2+$$>$$Mg2+$$>$$Ca2+$$>$$Sr2+$$>$$Ba2+I)$$ $$EM2+/M$$° values are negative.Most negative for $$Ra=Ba$$ and least negative for Be.$$J)$$ $$ERa2+/Ra$$°$$(most$$ $$negative)=EBa2+/Ba$$° $$Mg2+$$ > $$Ca2+$$ > $$Sr2+$$ > $$Ba2+$$ $$=$$ $$Ra2+$$ ;

A, B, C, D , E and F are the elements belonging to Second group of Modern periodic table. The correct trend of reducing power for these elements in aqueous solution is A = F > C > D > E>B. The element ‘C’ in the sequence is

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