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Q.

A+B⇌C+D If initially the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of A then what will be the equilibrium constant of reaction ?

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a

49

b

94

c

19

d

4

answer is D.

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Detailed Solution

A + B ⇌ C + D t=0; a a 0 0 teq.; (a-x) (a-x) x x ∵ [D]=2[A] ⇒ x=2(a-x) ⇒ x=2a/3 Now kc=[C][D][A][B]=2a/3×2a/3a/3×a/3=4

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