A+B⇌C+D . Initially the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of A then what will be equilibrium constant of reaction

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answer is D.

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Detailed Solution

A + B ⇌ C + D 1 1 0 0 Initial (1-x) (1-x) x x AT Equilibrium D=2[A] x=2(1-x) x=2-2x x=23 kC=x2(1-x)2=(x1-x)2 =((23)2(13)2) =22=4

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