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Q.

For 2A+B+C →Products , rate law is given by rate=k[A][B]2 & rate constant (k) is 2×10−6M−2s−1 . Then rate of the reaction become 2×10−9M−2s−1 only when     [A]           [B]            [C]

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a

0.1 M     0.1M      0.2 M

b

0.2 M     0.1 M     0.2 M

c

0.1 M     0.1 M     any value

d

0.2 M     0.2 M     0.1 M

answer is C.

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Detailed Solution

rate = K[A][B]2  [A][B]2=rateK=2×10−92×10−6                                =10−3 ∴   if [A]=0.1,[B]=0.1 then           [A][B]2=0.001
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