A→B,∆H=-10J mol-1 Ea(f) = 50 J mol-1
Then Ea(b) B→A in k j mol-1 will be?
∆H=-10J mol-1 It is an exothermic reaction Ea(b) = Ea(f) - ∆H = 50 - (-10) = 60 J mol-1 = 0.06 k J mol-1