First slide

13th group or boron group

Question

$B_{2} H_{6} + N H_{3} \overset{120^{0}}{\to} X$
What is X ?

Difficult

A

$B_{3} N_{3} H_{6}$
B

$B N$
C

${[B H_{2} {(N H_{3})}_{2}]}^{+} {[B H_{4}]}^{-}$
D

$B_{2} O_{3}$

Solution

Following are the actions of ammonia on diborane under different conditions.
$B_{2} H_{6} + 2 N H_{3} \overset{120^{0}}{\to} B_{2} H_{6} .2 N H_{3}$ $\equiv$ ${[B H_{2} {(N H_{3})}_{2}]}^{+} {[B H_{4}]}^{-}$
$3 B_{2} H_{6} + 2 N H_{3} \overset{200^{\circ} C}{\to} B_{3} N_{3} H_{6} + 12 H_{2}$
$B_{2} H_{6} + 2 N H_{3} \overset{200^{0}}{\to} B_{2} H_{6} .2 N H_{3}; 1 : 2 p r o p o r t i o n$
$B_{3} N_{3} H_{6} \overset{200^{\circ} C}{\to} 3 {(B N)}_{3} + 3 n H_{2}$

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