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B2H6+NH31200X . Where X is

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By Expert Faculty of Sri Chaitanya
a
B3N3H6
b
BN
c
BH2NH32+BH4−
d
B2O3
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detailed solution

Correct option is C

B3H6+2NH3→1200B2H6.2NH3 BH2NH32+BH4−


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