Balance the half reaction, NO2-→ H+NO3- and calculate the product of number of electrons and H+ ions involved in the balanced half reaction

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answer is B.

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Detailed Solution

NO2−+H2O→NO3−NO2−+H2O→NO3−+2H+NO2−+H2O→NO3−+2H++2e¯Product of number of electrons and H+ ions =2×2=4

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