First slide

Activity Series (OR) Electro chemicals series

Question

Based on the data given below, the correct order of reducing power is :
$\large F{e^{3 + }}_{\left( {aq} \right)} + \,e\, \to \,F{e^{2 + }}_{\left( {aq} \right)};\,{E^0}\, = \,0.77V$

$\large A{l^{3 + }}_{\left( {aq} \right)} + \,3e\, \to \,A{l_{\left( s \right)}};\,{E^0}\, = \, - 1.66V$

$\large B{r_{2\left( {aq} \right)}} + \,2e\,\, \to \,2B{r^ - }_{\left( {aq} \right)};\,{E^0}\, = \, + 1.08V$

Moderate

A

Br^– < Fe²⁺ < Al
B

Fe²⁺ < Al < Br^–
C

Al < Br^– < Fe²⁺
D

Al < Fe²⁺ < Br^–

Solution

Reducing power is ability to undergo oxidation. Electrode with lower SRP the right hand species readily looses electrons and reducing power is more.
$\operatorname{Reducing\,\,power\, \propto \frac{1}{{SRP}}$
Order is
Br^- < Fe⁺² < Al

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