Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Based on the following isotherms, select correct statements.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

For H2 at 0ºC, molecular attractive forces are weak and size effect dominates its behavior resulting that (Z>1)

b

For N2 at 0ºC, attractive forces are large enough to cause negative deviation upto 150 atm thus (Z<1) after which size effect dominates thus (Z>1)

c

For CO2, intermolecular attraction is large even at 40ºC resulting (Z<1) even at high pressures

d

For CO2 and N2¸two effects compensate each other  at a particular pressure where, Z=1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

1) For H2, attractive force is zero.Hence, pV−b=RTpV=RT+pbZ=pVRT=1+pbRTThen, Z > 12) For N2 (in low pressure range)P is low , V is highThus, (V-b)=Vp+aV2V=RTpV=RT−aVZ=pVRT=1−aRTVThus, Z < 13) As in (B)4) At a particular pressure (separately for CO2 and N2) ideal behavior is reached thus, Z=1
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon