Based on the following isotherms, select correct statements.

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For H2 at 0ºC, molecular attractive forces are weak and size effect dominates its behavior resulting that (Z>1)

For N2 at 0ºC, attractive forces are large enough to cause negative deviation upto 150 atm thus (Z<1) after which size effect dominates thus (Z>1)

For CO2, intermolecular attraction is large even at 40ºC resulting (Z<1) even at high pressures

For CO2 and N2¸two effects compensate each other at a particular pressure where, Z=1

answer is A.

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Detailed Solution

1) For H2, attractive force is zero.Hence, pV−b=RTpV=RT+pbZ=pVRT=1+pbRTThen, Z > 12) For N2 (in low pressure range)P is low , V is highThus, (V-b)=Vp+aV2V=RTpV=RT−aVZ=pVRT=1−aRTVThus, Z < 13) As in (B)4) At a particular pressure (separately for CO2 and N2) ideal behavior is reached thus, Z=1

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