Based on the following reaction,XeO64−(aq)+2F−(aq)+6H+(aq)⟶XeO3(g)+F2(g)+3H2O(l)∆G∘<0It can be concluded that

XeO64-↑(+8)+F-↑(-1)→XeO3↑+6+F2↑0Since, ∆G°<0, hence it is spontaneous in forward direction. Oxidation number of Xe decreases hence, it is an oxidising agent and oxidation number of F increases, hence it is a reducingagent.