Download the app

Covalent Bonding

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions

Based on VSEPR theory, the number of  F-Br-F angles which has close to 90 0 possible in a molecule of BrF5 will be _________


Hybridisation of Br in : BrF5=12(7+5)=6=sp3d2

Geometry = Octahedral
Due to one lp of e- 's, it has square pyramidal in shape.

It has eight (F-Br-F) bonds which are at 90°. There are

 1. F1BrF2     2. F2BrF3    3. F3BrF4

 4. F4BrF1    5. F1BrF5    6. F5BrF4

 7. F5BrF3    8. F5BrF2

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

Talk to our academic expert!


Are you a Sri Chaitanya student?


Create Your Own Test
Your Topic, Your Difficulty, Your Pace

Similar Questions

Find the number of lone pairs of electrons present in OF2 molecule.

phone icon
whats app icon