Q.

Based on VSEPR theory, the number of  F-Br-F angles which has close to 90 0 possible in a molecule of BrF5 will be _________

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answer is 8.

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Detailed Solution

Hybridisation of Br in : BrF5=12(7+5)=6=sp3d2Geometry = OctahedralDue to one lp of e- 's, it has square pyramidal in shape.It has eight (F-Br-F) bonds which are at 90°. There are 1. F1−Br−F2     2. F2−Br−F3    3. F3−Br−F4 4. F4−Br−F1    5. F1−Br−F5    6. F5−Br−F4 7. F5−Br−F3    8. F5−Br−F2
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