First slide

Enthalpy of Combustion

Question

Benzene burns in oxygen according to the equation 2C₆H_6(I) +15O_2(g) $\rightarrow$ 12CO_2(g)+ 6H₂O_(l). How many litres of oxygen are required at STP for the complete combustion of 39 g of liquid benzene?

Easy

Solution

$\large \mathop {\mathop {2{C_6}{H_6}(l)}\limits_{(2 \times 78g)}^{2moles} }\limits_{39g} + \mathop {\mathop {15{O_2}}\limits_{15(22.4l)}^{15mole} }\limits_{'X'l} \to 12C{O_2}(g) + 6{H_2}O(l)$
$\large X = \frac{39}{2 \times 78} \times 15(22.4)$
= 84 lit
Volume of O₂ required for the combustion of 39grams of C₆H₆ = 84 lit

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