Benzene burns in oxygen according to the equation 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) . How many litres of oxygen are required at STP for the complete combustion of 7.8 g of liquid benzene?

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11.2

22.4

16.8

answer is C.

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Detailed Solution

2×78 gm C6H6→15×22.4 lit O2 7.8gm C6H6→? =15×22.42×78×7.8 =16.8 lit

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