Q.

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is :

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a

168

b

192

c

188

d

182

answer is C.

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Detailed Solution

Valency of metal = 2; Eq. mass = 32. Thus:At. mass = Eq. mass x Valency; At. mass = 32 x 2 = 64∴ Mol. mass of M(NO3)2 = At. mass of M + 2 (At. mass of N) + 2 (3 x At. mass of  O) = 64 + (2 x 14) + 2 (3 x 16) = 188.
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