Questions
BOD of water is expressed in ppm of Oxygen. BOD of 100 kg water sample which requires 490 mg of acidified potassium dichromate to oxidize all the microorganisms will be
detailed solution
Correct option is B
GEW of K2Cr2O7/H+=49g; GEW of O2=8g; 49g of K2Cr2O7/H+=8g of O2; 49mg of K2Cr2O7/H+=8mg of O2; 105g of water-80 mg of O2 106g of water-800mg of O2 BOD of water =0.8g=0.8ppmSimilar Questions
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