Q.

BOD of water is expressed in ppm of Oxygen. BOD of 100 kg  water sample which requires  490 mg of acidified potassium dichromate to oxidize all the microorganisms will be

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a

1.6ppm

b

0.8ppm

c

80ppm

d

16ppm

answer is B.

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Detailed Solution

GEW of K2Cr2O7/H+=49g; GEW of O2=8g; 49g of  K2Cr2O7/H+=8g of O2;  49mg of  K2Cr2O7/H+=8mg of O2; 105g of water-80 mg of O2 106g of water-800mg of O2  BOD of water =0.8g=0.8ppm
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BOD of water is expressed in ppm of Oxygen. BOD of 100 kg  water sample which requires  490 mg of acidified potassium dichromate to oxidize all the microorganisms will be