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BOD of water is expressed in ppm of Oxygen. BOD of 100 kg  water sample which requires  490 mg of acidified potassium dichromate to oxidize all the microorganisms will be

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By Expert Faculty of Sri Chaitanya
a
1.6ppm
b
0.8ppm
c
80ppm
d
16ppm

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detailed solution

Correct option is B

GEW of K2Cr2O7/H+=49g; GEW of O2=8g; 49g of  K2Cr2O7/H+=8g of O2;  49mg of  K2Cr2O7/H+=8mg of O2; 105g of water-80 mg of O2 106g of water-800mg of O2  BOD of water =0.8g=0.8ppm


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