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BOD of water is expressed in ppm of Oxygen. BOD of 100 kg water sample which requires 490 mg of acidified potassium dichromate to oxidize all the microorganisms will be
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a
1.6ppm
b
0.8ppm
c
80ppm
d
16ppm
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Correct option is B
GEW of K2Cr2O7/H+=49g; GEW of O2=8g; 49g of K2Cr2O7/H+=8g of O2; 49mg of K2Cr2O7/H+=8mg of O2; 105g of water-80 mg of O2 106g of water-800mg of O2 BOD of water =0.8g=0.8ppmSimilar Questions
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