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BOH is a weak base, molar concentration of BOH that provides a OH- of 1.5 × 10-3 M  Kb BOH= 1.5 × 10-5 M is

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a
0.15 M
b
0.1515 M
c
0.0015 M
d
1.5 × 10-5 M

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detailed solution

Correct option is A

BOH  ⇌  B+  +  OH-  Kb=Cα2; α2=KbC ; α=KbC ; [OH-] =Cα By Ostwald's dilution law;  OH- = KbC                                           [OH-]2=KbC                       (1.5 × 10-3 )2=1.5 × 10-5 C                               C = 0.15 M

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