BOH is a weak base. Molar concentration of BOH that provides a [OH-] of 1 .5 x 10-3 M[Kb(BOH) = 1.5x 10-5M] is

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0.15 M

0.1515 M

0.0015 M

1.5×10−5M

answer is A.

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Detailed Solution

BOH⇌B++OH−By Ostwald's dilution law,OH−=KbC1.5×10−3=1.5×10−5×CC = 0.15 M

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