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Q.

Boiling point of 1 m sucrose solution will be (Kb of water is 0.52 K Kg mole-1)

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a

373.104 K

b

373.052 K

c

374.04 K

d

373.52 K

answer is D.

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Detailed Solution

∆Tb=Kbm     ∆Tb=0.521             =0.52 K Tb-To=0.52 K         Tb=373+0.52K             =373.52 K
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