The boiling point of a substance X at 1 atm pressure is 500 K. the enthalpy of vapourisation at the boiling point of X (l) is 80 kJ / mol. The molar specific heat of X(l) = 5 × 10-3 mol and Cp of X(g) = 5 × 10-4 kJ/mol.. What is the molar latent heat of vaporization of X(l) at 800 K and at 1 atm?
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a
Lesser than 80 kJ
b
Greater than 80 kJ
c
Equal to 80 kJ
d
Since 800K is the higher temperature than the boiling point of X (l); therefore, enthalpy of vaporization is not applicable.