Bond angle in H2O is explained by theory and bond angle in H2S , H2Se , H2Te is explained by
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a
VBT , VBT
b
VBT , VSEPR
c
VSEPR , VBT
d
VSEPR , VSEPR
answer is C.
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Detailed Solution
In H2O molecule , Oxygen atom has four electron pairs around it According to VSEPR theory, shape must be tetrahedralBut due to lp-lp repulsions bond angle decreases to 104.5oAnd water molecule is bent (or) angularIn H2S , H2Se , H2Te , H2Po the bond angle is around 90-93oIt is assumed that p-orbitals of central atom participate in bonding P-orbitals are 90o to each other , the bond angle is around 90o - 93oThus VBT explains the shapes of H2S , H2Se , H2Te , H2Po