Q.
The bond energy of C-H, C-C, C=C, and H-H bonds are 414, 347, 6L5, and 435 k] mol-1 at 298 K. The enthalpy change or the reaction:CH2=CH2+H2(g)→CH3−CH3(g)
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a
+ 125 kJ
b
- 125 kJ
c
+ 250 kJ
d
-250 kJ
answer is B.
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Detailed Solution
ΔH=−eC−C+6×eC−H+eC=C+4×eC−H+eH−H=−[347+6×414]+[615+4×414+435]=−125kJ
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