Bond enthalpies of P-P, O=O and P-O are p, q and s respectively. Enthalpy change for the process, P4+3O2→P4O6 is
4p + 3q - 6s
6p + 3q - 16s
4p + 3q - 12s
6p + 3q - 12s
6P-P+3O=O-12P-O=∆H
+6P + 3q - 12s = ∆H