Q.
Bond Enthalpy values of H-H, Cl-Cl are 436kJ/mole and 243kJ/mole respectively. Bond Enthalpy of H-Cl will be ∆f0HCl=-93kJ/mole
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
12H2g+12Cl2g →HClg; ∆H=-93kJ/mole H2g+Cl2g →2HClg; ∆H=-186kJ/mole ∆H=HR-HP -186=HH-H+HCl-Cl-2X -186=+436+243-2X 2X= (436+243+186)kJ/mole X=432.5 kJ/mole
Watch 3-min video & get full concept clarity