Q.
The bond enthalpy values of H-H, O=O bonds are 436 kJ/mole and 498 kJ/mole respectively. Standard enthalpy of formation of water is -286 kJ/mole. The bond enthalpy of O-H bond is equal to-----kJ/mole
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a
610
b
629
c
229.5
d
485.5
answer is D.
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Detailed Solution
H-H+12O=O → 2O-H, H=-286 kJ ;+436+12498 +-2x =-286 ; x=436+249+2862 x=485.5 kJ ; O-H bond enthalpy=485.5 kJ/mole ;
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