First slide

Enthalpy of Atomisation and bond dissociation

Question

The bond enthalpy values of H-H, O=O bonds are 436 kJ/mole and 498 kJ/mole respectively. Standard enthalpy of formation of water is -286 kJ/mole. The bond enthalpy of O-H bond is equal to-----kJ/mole

Moderate

A

610
B

629
C

229.5
D

485.5

Solution

$\begin{array}{l} H - H + \frac{1}{2} O = O \to 2 O - H, \\ H = - 286 kJ; + 436 + \frac{1}{2} (498) + (- 2 x) = - 286; \\ x = \frac{436 + 249 + 286}{2} \\ x = 485.5 kJ; \\ O - H bond enthalpy = 485.5 kJ / mole; \end{array}$

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