Bond length in H2 molecule is 'x' nm. The covalent radius of deuterium is
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a
'x' nm
b
2x nm
c
4x nm
d
x/2 nm
answer is D.
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Detailed Solution
Given, B.L [i.n nm]= xThe isotopes of an element differed by their masses but they have same bond lengths i.e., The bond length in H2,D2T2 are sameCovalent radii [Cr] Cr= Bond length 2Cr=x2nm