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Q.

The bond order in N2+ ion is

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a

1

b

2

c

2.5

d

3

answer is C.

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Detailed Solution

N2+ = KK[σ(2s)]2 [σ*(2s)]2 [π(2px)]2 [π(2py)]2 [σ(2pz)]1Here, Nb =7, Na=2 so that B.O. = No. of Nb− No. of Na2=52=2.5.
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The bond order in N2+ ion is