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Q.

The bond order in O2- ion is x, The value of x cannot be

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a

2

b

1

c

2.5

d

1.5

answer is A.

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Detailed Solution

The electronic configuration of O2−0:→iσ1s)2σ∗1s2(σ2s)2σ∗2s2σ2pz2τ2pc2π2py2π∗2px2π∗2py1Bond  order =12Nb−Na1210-7=32=1.5.
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