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Q.

The bond order of O2+is the same as in

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a

N2+

b

CN−

c

CO

d

NO+

answer is A.

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Detailed Solution

O2+15e−=KK∗(σ2s)2 σ∗2s2σ2px2,π2py2=π2pz2 π∗2py1= π∗2pz0 Hence, bond order =12(10−5)=2.5N2+13e−=KK∗(σ2s)2 σ∗2s2π2py2=π2pz2,σ2px1 Hence, Bond order =12(9−4)=2.5

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