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Boron nitride is isoelectronic with
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a
C2
b
B2
c
N2
d
O2
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Correct option is A
Boron nitride (BN),Total no. of electrons - Electrons of B + Electrons of N=5+7 =12C2, Total no. of electrons : 2 x Electrons of C=2 x 6 = 12Hence, BN and C2, arc isoelectronic.
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