First slide

Atomic and physical properties

Question

Boron nitride is isoelectronic with

Easy

A

$C_{2}$
B

$B_{2}$
C

$N_{2}$
D

$O_{2}$

Solution

Boron nitride (BN) = 12 electrons
B = 5 electrons
N = 7 electrons
$C_{2} = 12 e^{-}$

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