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Q.

For a broadcasted electromagnetic wave having frequency of 1200 KHz, calculate number of waves that will be formed in 2 km distance :

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a

8

b

4

c

16

d

2

answer is A.

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Detailed Solution

λ=cv=3×108m/s1200×103s−1=250m=0.25kmv¯=1λ=10.25=4 waves per km.; 8 waves in 2 Km ;          (or)ν-=νC=1200×103 s-13×108 m.s-1=4×10-3 m-1 ; ν- =4 Km-1
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