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Q.

A bubble of volume V1 is present in the bottom of a pond at l5°c and 1.5 atm pressure when it comes at the surface it observes a pressure of 1 atm at 25°C and has volume V2. The value of V2V1 is

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a

15.5

b

0.155

c

155.0

d

1.55

answer is D.

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Detailed Solution

p1=1.5 atm,T1=15°C=(15+273)K=288 Kp2=1 atm,T2=25°C=(25+273)=298 Kp1V1T1=p2V2T2p1T2T1p2=V2V1⇒ V2V1=1.5×298288×1=1.55
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