First slide

Common ion effect

Question

To a buffer solution of CH₃COOH and CH₃COONa, some HCl is added. Then the reaction involved is

Easy

A

$\large C{H_3}COOH\,\, + \,O{H^ - }\, \to \,C{H_3}CO{O^ - }\, + \,{H_2}O$
B

$C{H_3}CO{O^ - }\, + \,{H^ + }\, \to \,C{H_3}COO\,H$
C

$N{a^ + }\, + \,O{H^ - }\, \to \,NaO\,H$
D

$C{H_3}CO{O^ - }\, + \,N{a^ + }\, \to \,C{H_3}COONa$

Solution

Following is the given buffer,
$\mathop {C{H_3}COOH}\,\,\,\,\,\, \rightleftharpoons \,\,\,\,\mathop {C{H_3}CO{O^ - }}+ \mathop {H^ + }$

$\mathop {C{H_3}COONa}\ \,\,\,\,\,\, \rightleftharpoons \,\,\,\,\mathop {C{H_3}CO{O^ - }} + \mathop {H^ + }$
Incoming H⁺ ion from HCl, whichis acidic, will be neutralised by the conjugate base CH₃COO^- present in the buffer via the following reaction.
$C{H_3}CO{O^ - }\, + \,{H^ + }\, \to \,C{H_3}COO\,H$

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