A buffer solution is prepared by mixing equal concentration of a weak base with its salt of strong acid. Kb for the base is 10-9. pH of this buffer solution will be

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answer is C.

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Detailed Solution

∵pOH=pKb=−log⁡Kb (∵ [base] = [salt]) ∴pOH=pKb=−log⁡10−9=9 ∵ pH=14−pOH=14−9=5

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