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Q.

A bulb contains 1.6 g of O2. It contains

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a

0.05 mol of O2

b

3.011×1020 molecules of O2

c

11.2 L of O2 of STP

d

122 L of O2 at STP

answer is A.

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Detailed Solution

1. Moles of  O2=1.632=0.052. Molecules of O2=0.05×6.023×1023=3.011×10223. Volume of O2 at StP = 0.05×0.05×22.4=1.12L4. VO2 at SATP = 0.05×24.4=1.22L
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