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Q.

A bulb of unknown volume ‘V’ Contains an ideal gas at 2 atm pressure. It was connected to another evacuated bulb of volume 0.5 litre through a stopcock. When the stopcock was opened the pressure in each bulb became 0.5 atm. Then V is aprroximately

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Detailed Solution

PV =P1 V1 + P2 V22V =0.5 x V +0.5 x 0.52V - 0.5V =0.25V =0.25 ÷ 1.5 =0.166 lit
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