Q.

A button cell used in watches, functions as following Zn(s)+Ag2O(s)+H2O(l)⇌2Ag(s)+Zn2+(,)+2OH−(aq)If half-cell potentials are Zn2+(aq)+2e−⟶Zn(s);E∘=−0.76VAg2O(s)+H2O(l)+2e−⟶2Ag(s)+2OH−E∘=0.34V the cell potential will be

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1.1 V

0.42 V

0.84 V

1.34 V

answer is A.

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Detailed Solution

Anode is always the site of oxidation and cathode is the site of reduction, Thus, anode half-cell isZn2+(aq)+2e−⟶Zn(s);E∘=−0.76VCathode half-cell is Ag2O(s)+H2O(l)+2e−⟶2Ag(s)+2OH−(aq) E∘=0.34VEcell ∘=Ecathode ∘−Eanode ∘ =0.34−(−0.76) =1.1V

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