By passing 0.1 Faraday of electricity through fused sodium chloride, the amount of chlorine liberated is

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35.45 g

70.9 g

3.545 g

17.77 g

answer is C.

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Detailed Solution

1 F liberates 1 eq of Cl20.1 F liberates 0.1 eq of Cl2.Amount of chlorine liberated = 0.1 x 35.45 =3.545 gm

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