First slide

Solubility product(KSP)

Question

At 20°C, the ${Ag}^{+}$ ion concentration in a saturated solution of ${Ag}_{2} {CrO}_{4}$ is $1.5 \times 10^{- 4} mol / L$ . At 20°C, the solubility product of ${Ag}_{2} {CrO}_{4}$ will be

Moderate

A

$3.3750 \times 10^{- 12}$
B

$1.6875 \times 10^{- 10}$
C

$1.6875 \times 10^{- 12}$
D

$1.6875 \times 10^{11}$

Solution

${Ag}_{2} {CrO}_{4} ⇌ 2 {Ag}^{+} + {CrO}_{4}^{2 -}$
$[{CrO}_{4}^{2 -}] = \frac{1}{2} [{Ag}^{+}] = \frac{1.5 \times 10^{- 4}}{2} = 0.75 \times 10^{- 4}$
$K_{sp} = {[{Ag}^{+}]}^{2} [{CrO}_{4}^{2 -}]$
$= {(1.5 \times 10^{- 4})}^{2} (0.75 \times 10^{- 4})$
$= 1.6875 \times 10^{- 12}$

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